0.83t^2-7t+9=0

Solution for 0.83t^2-7t+9=0 equation:

0.83t^2-7t+9=0

a = 0.83; b = -7; c = +9;
Δ = b2-4ac
Δ = -72-4·0.83·9
Δ = 19.12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{19.12}}{2*0.83}=\frac{7-\sqrt{19.12}}{1.66}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{19.12}}{2*0.83}=\frac{7+\sqrt{19.12}}{1.66}
$